from django.conf.urls.defaults import *
from django.views.generic import list_detail
from books.models import Publisher

publisher_info = {
    "queryset" : Publisher.objects.all(),
}

urlpatterns = patterns('',
    (r'^publishers/$', list_detail.object_list, publisher_info)
)

That’s all the Python code we need to write. We still need to write a template, however. We could explicitly tell the object_list view which template to use by including a template_name key in the extra arguments dictionary, but in the absence of an explicit template Django will infer one from the object’s name. In this case, the inferred template will be "books/publisher_list.html" — the “books” part comes from the name of the app that defines the model, while the “publisher” bit is just the lowercased version of the model’s name.

This template will be rendered against a context containing a variable called object_list that contains all the publisher objects. A very simple template might look like the following:

{% extends "base.html" %}

{% block content %}
    <h2>Publishers</h2>
    <ul>
        {% for publisher in object_list %}
            <li>{{ publisher.name }}</li>
        {% endfor %}
    </ul>
{% endblock %}
That's really all there is to it.
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